AP Physics 1 · Lesson 1

Vectors, velocity and reference frames

Know Know it

A scalar has only a size (distance, speed, time). A vector has a size and a direction (displacement, velocity, acceleration, force). Choose a positive direction before you start, and in one dimension let the sign carry the direction.

Displacement is final position minus initial position, Δx=xf−xi\Delta x = x_f - x_i; distance is the length of the path. So average velocity is Δx/Δt\Delta x/\Delta t, while average speed is distance divided by time. The two have the same size only for one-way motion along a straight line.

In two dimensions, split each vector into perpendicular components. A vector of size A at angle θ from the x-axis has Ax=Acos⁡θA_x = A\cos\theta and Ay=Asin⁡θA_y = A\sin\theta. Add the components separately, then rebuild the result with A=Ax2+Ay2A = \sqrt{A_x^2 + A_y^2} and tan⁡θ=Ay/Ax\tan\theta = A_y/A_x.

Scalar and vector partners
Scalar (size only)Vector (size and direction)How they differ
DistanceDisplacementDistance adds up every step; displacement compares only the start and the finish
SpeedVelocitySpeed is never negative; the sign or angle of a velocity gives its direction
Average speedAverage velocityDistance over time versus displacement over time

Calculator On the exam

On the exam you may use a four-function, scientific or graphing calculator on both sections, and the testing app also has built-in scientific and graphing calculators. You get an equation sheet with reference tables too, so spend your effort on choosing the right relationship, not memorizing it. In these lessons, use g = 9.8 m/s² unless a problem gives another value. Set the calculator to degrees before you take a sine or cosine.

Worked example Easy

A warehouse robot drives 18 m north along an aisle, then turns around and drives 7 m south. The trip takes 25 s. What are the robot’s average speed and average velocity for the trip?

  1. Average speed 1.0 m/s; average velocity 0.44 m/s northAnswer
  2. Average speed 0.44 m/s; average velocity 1.0 m/s north
  3. Average speed 1.0 m/s; average velocity 1.0 m/s north
  4. Average speed 1.0 m/s; average velocity 0.44 m/s south

How to solve it

  1. Distance adds every leg: 18 m + 7 m = 25 m, so the average speed is 25 m / 25 s = 1.0 m/s.
  2. Displacement compares the start and the finish: 18 m north minus 7 m south leaves 11 m north.
  3. Average velocity = 11 m / 25 s = 0.44 m/s north.

Why each choice is right or wrong

  • A. Correct. The distance is 18 + 7 = 25 m, so the average speed is 25 m / 25 s = 1.0 m/s. The displacement is 18 - 7 = 11 m north, so the average velocity is 11 m / 25 s = 0.44 m/s north.
  • B. Incorrect. Average speed 0.44 m/s swaps the two quantities: the speed uses the 25 m distance and the velocity uses the 11 m displacement.
  • C. Incorrect. Average velocity 1.0 m/s north divides the whole 25 m path by the time; velocity uses only the 11 m net displacement.
  • D. Incorrect. Average velocity 0.44 m/s south has the wrong direction: the robot ends 11 m north of where it started.

Trap Average speed is not the size of average velocity

Whenever a trip doubles back or bends, the distance is longer than the displacement, so the average speed is larger than the size of the average velocity. A delivery driver who ends a shift back at the depot has a large average speed and an average velocity of zero.

Explain Explain it

Task verbs: calculate, explain

Every velocity is measured relative to something. If A moves at v⃗AB\vec v_{AB} relative to B, and B moves at v⃗BC\vec v_{BC} relative to C, then A moves at v⃗AC=v⃗AB+v⃗BC\vec v_{AC} = \vec v_{AB} + \vec v_{BC} relative to C. Add the velocities as vectors: along one line, add them with their signs; at right angles, use the Pythagorean theorem.

When you explain a result, name the frame of each velocity: relative to the walkway, relative to the ground, relative to the air. Most relative-motion mistakes come from mixing two frames in one equation.

Worked example Medium

An airport walkway is 66 m long and moves at 0.90 m/s relative to the floor. A traveler walks along it, in the direction it moves, at 1.3 m/s relative to the walkway. How long does the traveler take to get from one end to the other?

  1. 30 sAnswer
  2. 51 s
  3. 73 s
  4. 165 s

How to solve it

  1. Both velocities point the same way, so add them: 1.3 + 0.90 = 2.2 m/s relative to the floor.
  2. The 66 m length is measured along the floor, so use the floor-frame speed.
  3. t = 66 m / 2.2 m/s = 30 s.

Why each choice is right or wrong

  • A. Correct. Relative to the floor the traveler moves at 1.3 + 0.90 = 2.2 m/s, so the time is 66 m / 2.2 m/s = 30 s.
  • B. Incorrect. 51 s uses only the walking speed, 1.3 m/s, which is measured relative to the walkway, not the floor.
  • C. Incorrect. 73 s uses only the walkway’s 0.90 m/s, as if the traveler stood still.
  • D. Incorrect. 165 s subtracts the speeds (0.40 m/s); the traveler walks in the same direction as the walkway, so the speeds add.

Calculate Your turn

A jogger runs 600 m due north and then 800 m due west, taking 400 s in all. Calculate the size of her average velocity and her average speed for the run, and explain why the two values differ.

Write it, then compare. Nothing you type here is saved or graded.

Compare with a model answer

A full answer does this

  • Gives 2.5 m/s for the size of the average velocity
  • Gives 3.5 m/s for the average speed
  • Explains that the average speed is larger because the distance traveled is longer than the size of the displacement

Model answer

The displacement is 6002+8002=1,000\sqrt{600^2 + 800^2} = 1{,}000 m, so the average velocity has a size of 1,000 m / 400 s = 2.5 m/s (pointing about 53 degrees west of north). The distance traveled is 600 + 800 = 1,400 m, so the average speed is 1,400 m / 400 s = 3.5 m/s. The average speed is larger because the distance traveled, 1,400 m along the two legs, is longer than the size of the displacement, 1,000 m in a straight line.

Apply Apply it

Practice these topics. AP Practice questions on exactly what this lesson covers, with an explanation for every answer.