AP Chemistry · Summary

Unit 8 summary

  1. pH = −log⁡[H3O+]-\log[\text{H}_3\text{O}^+]; at 25 °C, Kw=1.0×10−14K_w = 1.0 \times 10^{-14} and pH + pOH = 14.00. Neutral means equal ion concentrations, which is pH 7.00 only at 25 °C.
  2. Strong acids and bases ionize completely: count every hydroxide in a formula like Ba(OH)2\text{Ba(OH)}_2.
  3. For a weak acid, [H3O+]≈KaC[\text{H}_3\text{O}^+] \approx \sqrt{K_a C} when under 5 percent ionizes; for a weak base, [OH−]≈KbC[\text{OH}^-] \approx \sqrt{K_b C}. For a conjugate pair, KaKb=KwK_a K_b = K_w.
  4. A buffer holds a weak acid and its conjugate base; pH = pKa+log⁡([A−]/[HA])\text{p}K_a + \log([\text{A}^-]/[\text{HA}]), and it works best within one unit of the pKa\text{p}K_a.
  5. When strong acid or base is added to a buffer, react it first in moles, then use the buffer equation.
  6. At the equivalence point, moles of titrant match moles of analyte; for a weak acid with a strong base the pH there is above 7.
  7. At the half-equivalence point, pH = pKa\text{p}K_a; choose an indicator whose color change includes the equivalence-point pH.