AP Calculus AB · Unit 1

Unit 1: Limits and Continuity

How to read one-sided and two-sided limits from a graph or a table

How to find limits with algebra: substitution, factoring, rationalizing, special trig limits and the squeeze theorem

The three conditions for continuity at a point, and the three kinds of discontinuity

What the Intermediate Value Theorem guarantees, and what it needs

Vertical asymptotes from infinite limits, and horizontal asymptotes from limits at infinity

On the exam

About a tenth of the multiple-choice section by our estimate, roughly 4 or 5 of its 42 questions

Limit and continuity questions come in both the no-calculator and the calculator parts, and free-response questions often ask you to back up a claim about continuity or about a value a function must reach; the FRQ lesson here trains that justification

Key terms

17 terms. Say what each one means, then open the card to check.

  • Limit

    The number f(x)f(x) gets as close to as you like when xx is close enough to aa on both sides. The value f(a)f(a) itself plays no part.

    Example. If f(x)f(x) is 4.9, 4.99, 5.01 and 5.1 at inputs closing in on 2 from both sides, a table suggests lim⁡x→2f(x)=5\lim_{x \to 2} f(x) = 5, whatever f(2)f(2) is.

  • One-sided limit

    The number f(x)f(x) approaches as xx nears aa from one side only: lim⁡x→a−\lim_{x \to a^-} uses inputs below aa and lim⁡x→a+\lim_{x \to a^+} uses inputs above aa.

    Example. If a graph runs at height 1 just left of x=0x = 0 and at height 3 just right of it, the left-hand limit at 0 is 1 and the right-hand limit is 3.

  • A limit that does not exist

    A two-sided limit fails to exist when the one-sided limits differ, when the outputs grow without bound, or when they keep swinging without settling.

    Example. sin⁡(1x)\sin\left(\frac{1}{x}\right) swings between -1 and 1 infinitely often as xx nears 0, so its limit at 0 does not exist.

  • Direct substitution

    For a function that is continuous at aa, such as a polynomial, the limit at aa is simply the value of the function at aa.

    Example. lim⁡x→3(x2+1)=32+1=10\lim_{x \to 3}(x^2 + 1) = 3^2 + 1 = 10.

  • Indeterminate form 00\frac{0}{0}

    What you get when substituting into a quotient makes the top and the bottom both 0. It tells you nothing about the limit yet: rewrite the expression and substitute again.

    Example. x2−16x−4\frac{x^2 - 16}{x - 4} gives 00\frac{0}{0} at 4, but it equals x+4x + 4 for x≠4x \ne 4, so its limit at 4 is 8.

  • Rationalizing

    Multiplying the top and bottom of a quotient by the conjugate of a square-root expression, to clear a 00\frac{0}{0} form.

    Example. For x≠25x \ne 25, x−5x−25=1x+5\frac{\sqrt{x} - 5}{x - 25} = \frac{1}{\sqrt{x} + 5}, so the limit as x→25x \to 25 is 110\frac{1}{10}.

  • Squeeze theorem

    If g(x)≤f(x)≤h(x)g(x) \le f(x) \le h(x) for xx near aa, and gg and hh both have limit LL at aa, then ff also has limit LL at aa.

    Example. Near 2, −(x−2)2≤(x−2)2cos⁡(1x−2)≤(x−2)2-(x-2)^2 \le (x-2)^2\cos\left(\frac{1}{x-2}\right) \le (x-2)^2, and both bounds go to 0, so the middle function has limit 0 at 2.

  • The limit of sin⁡xx\frac{\sin x}{x}

    lim⁡x→0sin⁡xx=1\lim_{x \to 0}\frac{\sin x}{x} = 1 when xx is in radians. Many trig limits reduce to it.

    Example. tan⁡xx=sin⁡xx⋅1cos⁡x\frac{\tan x}{x} = \frac{\sin x}{x} \cdot \frac{1}{\cos x}, so lim⁡x→0tan⁡xx=1⋅1=1\lim_{x \to 0}\frac{\tan x}{x} = 1 \cdot 1 = 1.

  • Continuous at a point

    ff is continuous at aa when f(a)f(a) is defined, lim⁡x→af(x)\lim_{x \to a} f(x) exists, and the two are equal.

    Example. If g(1)=6g(1) = 6 and g(x)g(x) approaches 6 from both sides of 1, then gg is continuous at 1.

  • Removable discontinuity

    A point where the limit exists but the function value is missing or different from it. On a graph it is a hole, and redefining one value fixes it.

    Example. x2−xx\frac{x^2 - x}{x} is undefined at 0 but has limit -1 there, so defining its value at 0 as -1 removes the gap.

  • Jump discontinuity

    A point where both one-sided limits exist but are different numbers, so the graph jumps from one height to another.

    Example. A parking fee that is 5 dollars for stays up to one hour and 8 dollars for longer stays has a jump at one hour.

  • Infinite discontinuity

    A point where the function grows without bound on at least one side, so its graph has a vertical asymptote there.

    Example. 1(x+2)2\frac{1}{(x+2)^2} has an infinite discontinuity at x=−2x = -2: its outputs pass every height as xx nears -2.

  • Intermediate Value Theorem

    If ff is continuous on the closed interval [a,b][a, b] and NN is strictly between f(a)f(a) and f(b)f(b), then f(c)=Nf(c) = N for at least one cc strictly between aa and bb.

    Example. A temperature that changes continuously from 12 degrees at 6 a.m. to 20 degrees at noon must equal 15 degrees at some moment in between.

  • Infinite limit

    A statement such as lim⁡x→af(x)=∞\lim_{x \to a} f(x) = \infty: the outputs grow without bound near aa. The limit still does not exist as a number; the symbol says how it fails.

    Example. lim⁡x→01x2=∞\lim_{x \to 0}\frac{1}{x^2} = \infty, since 1x2\frac{1}{x^2} is above 100 whenever 0<∣x∣<0.10 < |x| < 0.1 and keeps growing.

  • Vertical asymptote

    The line x=ax = a is a vertical asymptote when f(x)f(x) grows without bound, toward ∞\infty or −∞-\infty, as xx approaches aa from at least one side.

    Example. lim⁡x→−4+1x+4=∞\lim_{x \to -4^+}\frac{1}{x + 4} = \infty, so x=−4x = -4 is a vertical asymptote of y=1x+4y = \frac{1}{x + 4}.

  • Limit at infinity

    The number f(x)f(x) approaches as xx grows without bound (x→∞x \to \infty) or decreases without bound (x→−∞x \to -\infty).

    Example. As x→∞x \to \infty, 5x\frac{5}{x} shrinks toward 0, so lim⁡x→∞5x=0\lim_{x \to \infty}\frac{5}{x} = 0.

  • Horizontal asymptote

    The line y=Ly = L is a horizontal asymptote when f(x)f(x) approaches LL as x→∞x \to \infty or as x→−∞x \to -\infty. It describes the ends of the graph only.

    Example. lim⁡x→∞10x−14x+7=104=2.5\lim_{x \to \infty}\frac{10x - 1}{4x + 7} = \frac{10}{4} = 2.5, so y=2.5y = 2.5 is a horizontal asymptote.

In this unit

  1. Finding limits: graphs, tables and algebra
  2. Continuity and the Intermediate Value Theorem
  3. Asymptotes and limits at infinity
  4. Justify continuity and use the IVT
  5. Summary
  6. Mastery quiz