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The real test, rehearsed.

98 questions across four modules, in the digital SAT’s order and on its timing, with a highlighter, a question map and a timer you can see.

A Peakscor full-length test in progress: Reading and Writing, Test A, Module 1 of 4, question 7 of 27, with the passage, four answer choices, a highlighter, a 24:18 timer and Flag, Back and Next buttons.

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  2. 2

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    Every question is tagged by domain and skill, and every answer comes with an explanation.

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Built around the real SAT blueprint.

Every question is tagged by section, domain, skill and difficulty, so you can practice exactly what you need. Full tests run like test day: two Reading & Writing modules, a break, then two Math modules.

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Not just the right letter: how to get there, and why the tempting answer is wrong.

MathProblem-Solving and Data AnalysisHard

A store raises the price of a jacket by 20%. Later, it lowers the new price by 20%. The final price is what percent of the original price?

A80%
B96%Correct
C100%The trap
D104%

Check with $100: $100then$120then$96

  1. Turn each change into a multiplier.

    Up 20% means × 1.20. Down 20% means × 0.80.

  2. Apply them in order.

    1.20 × 0.80 = 0.96

  3. Read the answer.

    The final price is 96% of the original. That’s B.

  4. Why not 100%?

    The 20% cut is taken from the higher price, so it removes more than the 20% increase added.

Test day

What test day looks like.

Every Peakscor full test follows this order. In the standard tests, the second module of each section adapts to how you did on the first.

  1. Reading & Writing · Module 1

    27 questions32 min

  2. Reading & Writing · Module 2

    27 questions32 min

    Adapts to how you did on Module 1.
  3. Break

    10 min

  4. Math · Module 1

    22 questions35 min

  5. Math · Module 2

    22 questions35 min

    Adapts to how you did on Module 1.

98 questions · 2 hr 14 min of testing, plus the break

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FAQ

Questions, answered.

The Daily, plus 36 practice questions every day: 12 easy, 12 medium and 12 hard, each with a full explanation. Full-length Test A, Challenge Test 1 and all 1,023 vocabulary words are free too. No card needed.

Pro is $20 a month or $200 a year: unlimited practice with no daily limit, plus every full-length test and Challenge test. Peak is $29 a month or $280 a year: everything in Pro, plus the full Learn course and Peak Plan. Cancel anytime from your account.

98 questions across four modules, in the digital SAT’s order: Reading & Writing Module 1 and Module 2 (27 questions each), a 10-minute break, then Math Module 1 and Module 2 (22 questions each). On official timing that’s 2 hr 14 min of testing. You get estimated section scores and a total at the end.

Yes. In the standard full-length tests, Module 2 of each section is the harder version if you get 60% or more of Module 1 right, and the easier version if you don’t. Challenge tests use the hardest material throughout.

Official timing, extended 1.5× time, or untimed, on every test, including the free ones. Extended time allows 48 minutes for each Reading & Writing module and about 52 for each Math module. Untimed removes the clock so you can focus on accuracy.

A quick run with three hearts. Each right answer builds your streak: the questions get harder as it grows, and your points multiply (×2 from three in a row, ×3 from six). A miss costs a heart and drops you back to easy. Best is your longest streak.

Every day at midnight. You get a fresh 12 easy, 12 medium and 12 hard.

No. Peakscor is an independent SAT practice tool, not affiliated with the College Board. Scores shown are estimates.

Your next point starts today.

Free, no card.

One-variable data · Lesson 2

Frequency tables, dot plots and histograms

The SAT often shows data as a summary instead of a list. A frequency table lists each value once, next to its frequency, the number of times it occurs. A dot plot shows the same thing with a stack of dots above each value, one dot per data value. A bar graph of frequencies works the same way, with bar heights in place of dots.

The number of data values is the sum of the frequencies, not the number of rows. To get the sum of the data, multiply each value by its frequency and add the products. Then mean = (sum of value × frequency) ÷ (sum of frequencies). For example, a value of 8 that appears 5 times adds 8⋅5=408 \cdot 5 = 40 to the sum and 5 to the count.

For the median, imagine writing every value out in order. With nn values the median is at position n+12\frac{n + 1}{2} (halfway between two positions when nn is even). Add the frequencies from the smallest value up until the running total reaches that position. The middle row of the table is the median only if the counts happen to put it there.

A histogram groups values into intervals, such as 10 to 19, and each bar shows how many values fall in that interval. You can't see the exact values, so you can't find the exact mean or median. You can usually find which interval contains the median with the same running-total method: it works when the median's position (both middle positions, if the count is even) falls inside one bar.

Worked example Easy

The table shows the number of pets owned by each of the 20 students in a class.

Number of petsNumber of students
04
17
25
33
41

What is the mean number of pets owned by these 20 students?

  1. 11
  2. 1.51.5Answer
  3. 22
  4. 44

How to solve it

  1. The number of students is the sum of the frequencies: 4+7+5+3+1=204 + 7 + 5 + 3 + 1 = 20.
  2. Multiply each number of pets by its frequency and add: 0⋅4+1⋅7+2⋅5+3⋅3+4⋅1=0+7+10+9+4=300 \cdot 4 + 1 \cdot 7 + 2 \cdot 5 + 3 \cdot 3 + 4 \cdot 1 = 0 + 7 + 10 + 9 + 4 = 30 pets in all.
  3. The mean is 3020=1.5\frac{30}{20} = 1.5 pets per student.

Why each choice is right or wrong

  • A. Incorrect. 1 is the median (and the mode): in order, the 10th and 11th students both own 1 pet. The question asks for the mean, 3020=1.5\frac{30}{20} = 1.5.
  • B. Correct. The 20 students own 0⋅4+1⋅7+2⋅5+3⋅3+4⋅1=300 \cdot 4 + 1 \cdot 7 + 2 \cdot 5 + 3 \cdot 3 + 4 \cdot 1 = 30 pets, so the mean is 3020=1.5\frac{30}{20} = 1.5.
  • C. Incorrect. 2 is the mean of the first column alone, 0+1+2+3+45=2\frac{0 + 1 + 2 + 3 + 4}{5} = 2. That counts each number of pets once, no matter how many students own it.
  • D. Incorrect. 4 is the mean of the frequency column, 205=4\frac{20}{5} = 4. The frequencies count students; they are not numbers of pets.

Worked example Medium

The dot plot shows the number of goals a soccer team scored in each of its 15 games this season.
Goals scored in each of 15 games1234567012345Goals in a gameNumber of games
Goals scored in each of 15 games Dot plot of 15 games, one dot per game. Dots above each number of goals: 1 goal, 2 dots; 2 goals, 4 dots; 3 goals, 3 dots; 4 goals, 2 dots; 5 goals, 1 dot; 6 goals, 2 dots; 7 goals, 1 dot.

What is the median number of goals per game?

  1. 22
  2. 33Answer
  3. 3.43.4
  4. 44

How to solve it

  1. Each dot is one game, so there are 15 values. The median is the value at position 15+12=8\frac{15 + 1}{2} = 8.
  2. Count dots from the left: the 1-goal stack holds games 1 and 2, the 2-goal stack holds games 3 through 6, and the 3-goal stack holds games 7 through 9.
  3. The 8th game is in the 3-goal stack, so the median is 3 goals.

Why each choice is right or wrong

  • A. Incorrect. 2 goals has the tallest stack, so it is the mode. The median is the 8th of the 15 values in order, and only 6 values are 1 or 2, so the 8th is 3.
  • B. Correct. There are 15 values, so the median is the 8th. The running totals are 2 (1 goal), 6 (2 goals) and 9 (3 goals), so the 8th value is 3.
  • C. Incorrect. 3.4 is the mean: 1⋅2+2⋅4+3⋅3+4⋅2+5⋅1+6⋅2+7⋅115=5115=3.4\frac{1 \cdot 2 + 2 \cdot 4 + 3 \cdot 3 + 4 \cdot 2 + 5 \cdot 1 + 6 \cdot 2 + 7 \cdot 1}{15} = \frac{51}{15} = 3.4. The question asks for the median.
  • D. Incorrect. 4 is the middle of the scale from 1 to 7. The median depends on where the dots are, and 9 of the 15 dots sit at 3 goals or fewer.

Trap Averaging the frequency column

In a table of values and frequencies, the frequency column counts how many times each value occurs. Adding the frequencies gives the number of data values, not their total, and the mean of the frequencies is not the mean of the data. Multiply each value by its frequency first.

Trap Taking the middle row or the tallest bar

The middle row of a frequency table, the middle of a graph's scale and the tallest bar or stack are all tempting, and in general none of them is the median. Find the median's position, n+12\frac{n + 1}{2}, and count frequencies up to it.

Desmos When Desmos is faster

For the mean of a frequency table, type the values and the frequencies as two lists: V = [0, 1, 2, 3, 4] and N = [4, 7, 5, 3, 1]. Then type total(VN)/total(N). Desmos multiplies the lists term by term, so total(VN) is the sum of the data, 30, and total(N) is the number of values, 20, giving 1.5.

Don't type mean(N). That is the mean of the frequencies, the trap from this lesson.

For a median, counting frequencies by hand is quicker than typing every value out. For a histogram, Desmos can't help with the median: the exact values aren't given.

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Full-length tests

Each test mirrors the digital SAT: 98 questions across four modules, 2 hr 14 min on official timing.

A little harder than the real SAT. These tests can run slightly tougher than test day, which makes them good practice: if you can handle these, the real one should feel easier. No question appears in more than one test, Challenge Tests included.

Challenge Tests Hardest of the hardest

Same 98-question format, but every question is drawn from the toughest SAT material: Challenging-tier math throughout and the hardest reading.

Vocab

Study the classic SAT vocabulary list. Browse, flip flashcards, or quiz yourself.

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