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A Peakscor full-length test in progress: Reading and Writing, Test A, Module 1 of 4, question 7 of 27, with the passage, four answer choices, a highlighter, a 24:18 timer and Flag, Back and Next buttons.

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Every question is tagged by section, domain, skill and difficulty, so you can practice exactly what you need. Full tests run like test day: two Reading & Writing modules, a break, then two Math modules.

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MathProblem-Solving and Data AnalysisHard

A store raises the price of a jacket by 20%. Later, it lowers the new price by 20%. The final price is what percent of the original price?

A80%
B96%Correct
C100%The trap
D104%

Check with $100: $100then$120then$96

  1. Turn each change into a multiplier.

    Up 20% means × 1.20. Down 20% means × 0.80.

  2. Apply them in order.

    1.20 × 0.80 = 0.96

  3. Read the answer.

    The final price is 96% of the original. That’s B.

  4. Why not 100%?

    The 20% cut is taken from the higher price, so it removes more than the 20% increase added.

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Every Peakscor full test follows this order. In the standard tests, the second module of each section adapts to how you did on the first.

  1. Reading & Writing · Module 1

    27 questions32 min

  2. Reading & Writing · Module 2

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  3. Break

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  4. Math · Module 1

    22 questions35 min

  5. Math · Module 2

    22 questions35 min

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98 questions · 2 hr 14 min of testing, plus the break

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The Daily, plus 36 practice questions every day: 12 easy, 12 medium and 12 hard, each with a full explanation. Full-length Test A, Challenge Test 1 and all 1,023 vocabulary words are free too. No card needed.

Unlimited practice with no daily limit, plus every full-length test and Challenge test. Pro is $20 a month or $180 a year. Checkout isn’t open yet, so nothing can be bought today.

98 questions across four modules, in the digital SAT’s order: Reading & Writing Module 1 and Module 2 (27 questions each), a 10-minute break, then Math Module 1 and Module 2 (22 questions each). On official timing that’s 2 hr 14 min of testing. You get estimated section scores and a total at the end.

Yes. In the standard full-length tests, Module 2 of each section is the harder version if you get 60% or more of Module 1 right, and the easier version if you don’t. Challenge tests use the hardest material throughout.

Official timing, extended 1.5× time, or untimed, on every test, including the free ones. Extended time allows 48 minutes for each Reading & Writing module and about 52 for each Math module. Untimed removes the clock so you can focus on accuracy.

A quick run with three hearts. Each right answer builds your streak: the questions get harder as it grows, and your points multiply (×2 from three in a row, ×3 from six). A miss costs a heart and drops you back to easy. Best is your longest streak.

Every day at midnight. You get a fresh 12 easy, 12 medium and 12 hard.

No. Peakscor is an independent SAT practice tool, not affiliated with the College Board. Scores shown are estimates.

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Systems of linear equations · Lesson 1

How many solutions: parallel and identical lines

Each linear equation is a line, and a solution to the system is a point on both lines. Two lines in a plane can meet in only three ways, so a system of two linear equations has exactly one solution, no solution or infinitely many.

Different slopes: the lines cross once, so there is exactly one solution. **Same slope, different yy-intercepts: the lines are parallel and never meet, so there is no solution. Same slope and same yy-intercept: the two equations describe the same line, so every point on it is a solution and there are infinitely many**.

To compare, put both equations in the same form. Solving each for yy shows the slope and intercept: 6x−2y=106x - 2y = 10 becomes y=3x−5y = 3x - 5. For two equations in the form ax+by=cax + by = c, a faster test is to ask whether one equation's left side is a multiple of the other's. If it isn't, the slopes differ and there is exactly one solution. If it is, multiply the whole equation by that number and compare the right sides: equal right sides mean the same line, different right sides mean parallel lines.

For example, doubling x+2y=5x + 2y = 5 gives 2x+4y=102x + 4y = 10. Paired with 2x+4y=102x + 4y = 10, the system has infinitely many solutions. Paired with 2x+4y=72x + 4y = 7, it has none.

When a constant such as kk appears, work backward. For no solution, choose kk so that one left side is a multiple of the other, then confirm the right sides do not match after scaling. For infinitely many, the right sides must match too.

How many solutions a system of two linear equations has
Slopes and interceptsExampleNumber of solutions
Different slopesy=2x+1y = 2x + 1 and y=−x+4y = -x + 4Exactly one, (1,3)(1, 3)
Same slope, different yy-interceptsy=2x+1y = 2x + 1 and y=2x−3y = 2x - 3None (parallel lines)
Same slope, same yy-intercepty=2x+1y = 2x + 1 and 4x−2y=−24x - 2y = -2Infinitely many (the same line)

Worked example Easy

y=3x+2y = 3x + 2

6x−2y=106x - 2y = 10

How many solutions does the given system of equations have?

  1. ZeroAnswer
  2. Exactly one
  3. Exactly two
  4. Infinitely many

How to solve it

  1. Put the second equation in slope-intercept form. Subtract 6x6x from both sides: −2y=−6x+10-2y = -6x + 10. Divide by −2-2: y=3x−5y = 3x - 5.
  2. Compare with y=3x+2y = 3x + 2. Both lines have slope 3, but the yy-intercepts are 2 and −5-5.
  3. Same slope with different intercepts means parallel lines, which never meet. The system has zero solutions.

Why each choice is right or wrong

  • A. Correct. The second equation is y=3x−5y = 3x - 5. It has the same slope as y=3x+2y = 3x + 2 but a different intercept, so the lines are parallel and never meet.
  • B. Incorrect. This compares the 3 in the first equation with the 6 in the second before rewriting. The slope of 6x−2y=106x - 2y = 10 is 3, not 6, so the slopes are equal.
  • C. Incorrect. Two different lines can cross at most once, so a system of two linear equations can't have exactly two solutions.
  • D. Incorrect. Infinitely many solutions would need the same intercept as well, but the intercepts are 2 and −5-5. Setting the equations equal gives 3x+2=3x−53x + 2 = 3x - 5, or 2=−52 = -5, which is never true.

Worked example Medium

2x+3y=72x + 3y = 7

kx+9y=12kx + 9y = 12

In the given system of equations, kk is a constant. For what value of kk does the system have no solution?

  1. −6-6
  2. 23\frac{2}{3}
  3. 22
  4. 66Answer

How to solve it

  1. No solution means parallel lines, so the second left side must be a multiple of the first. The yy-coefficient went from 3 to 9, so the multiple is 3.
  2. Multiply the whole first equation by 3: 6x+9y=216x + 9y = 21. For the left sides to match, k=6k = 6.
  3. Check the right sides: 21 and 12 are different, so the lines are parallel, not the same line. With k=6k = 6 the system has no solution.

Why each choice is right or wrong

  • A. Incorrect. This sets the slopes as opposites instead of equal. The first slope is −23-\frac{2}{3}, and setting −k9=23-\frac{k}{9} = \frac{2}{3} gives k=−6k = -6. Parallel lines have equal slopes, and with k=−6k = -6 the lines cross once.
  • B. Incorrect. This writes the ratio upside down: k2=39\frac{k}{2} = \frac{3}{9} gives k=23k = \frac{2}{3}. The second equation's coefficients are 3 times the first's, so k2=93\frac{k}{2} = \frac{9}{3}.
  • C. Incorrect. This copies the first equation's xx-coefficient without scaling it. With k=2k = 2 the slopes are −23-\frac{2}{3} and −29-\frac{2}{9}, which differ, so the system has exactly one solution.
  • D. Correct. Tripling the first equation gives 6x+9y=216x + 9y = 21. With k=6k = 6 the left sides match but the right sides, 21 and 12, don't, so the lines are parallel.

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