Digital SAT practice

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98 questions across four modules, in the digital SAT’s order and on its timing, with a highlighter, a question map and a timer you can see.

A Peakscor full-length test in progress: Reading and Writing, Test A, Module 1 of 4, question 7 of 27, with the passage, four answer choices, a highlighter, a 24:18 timer and Flag, Back and Next buttons.

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Every question is tagged by section, domain, skill and difficulty, so you can practice exactly what you need. Full tests run like test day: two Reading & Writing modules, a break, then two Math modules.

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MathProblem-Solving and Data AnalysisHard

A store raises the price of a jacket by 20%. Later, it lowers the new price by 20%. The final price is what percent of the original price?

A80%
B96%Correct
C100%The trap
D104%

Check with $100: $100then$120then$96

  1. Turn each change into a multiplier.

    Up 20% means × 1.20. Down 20% means × 0.80.

  2. Apply them in order.

    1.20 × 0.80 = 0.96

  3. Read the answer.

    The final price is 96% of the original. That’s B.

  4. Why not 100%?

    The 20% cut is taken from the higher price, so it removes more than the 20% increase added.

Test day

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Every Peakscor full test follows this order. In the standard tests, the second module of each section adapts to how you did on the first.

  1. Reading & Writing · Module 1

    27 questions32 min

  2. Reading & Writing · Module 2

    27 questions32 min

    Adapts to how you did on Module 1.
  3. Break

    10 min

  4. Math · Module 1

    22 questions35 min

  5. Math · Module 2

    22 questions35 min

    Adapts to how you did on Module 1.

98 questions · 2 hr 14 min of testing, plus the break

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The Daily, plus 36 practice questions every day: 12 easy, 12 medium and 12 hard, each with a full explanation. Full-length Test A, Challenge Test 1 and all 1,023 vocabulary words are free too. No card needed.

Unlimited practice with no daily limit, plus every full-length test and Challenge test. Pro is $20 a month or $180 a year. Checkout isn’t open yet, so nothing can be bought today.

98 questions across four modules, in the digital SAT’s order: Reading & Writing Module 1 and Module 2 (27 questions each), a 10-minute break, then Math Module 1 and Module 2 (22 questions each). On official timing that’s 2 hr 14 min of testing. You get estimated section scores and a total at the end.

Yes. In the standard full-length tests, Module 2 of each section is the harder version if you get 60% or more of Module 1 right, and the easier version if you don’t. Challenge tests use the hardest material throughout.

Official timing, extended 1.5× time, or untimed, on every test, including the free ones. Extended time allows 48 minutes for each Reading & Writing module and about 52 for each Math module. Untimed removes the clock so you can focus on accuracy.

A quick run with three hearts. Each right answer builds your streak: the questions get harder as it grows, and your points multiply (×2 from three in a row, ×3 from six). A miss costs a heart and drops you back to easy. Best is your longest streak.

Every day at midnight. You get a fresh 12 easy, 12 medium and 12 hard.

No. Peakscor is an independent SAT practice tool, not affiliated with the College Board. Scores shown are estimates.

Your next point starts today.

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Linear inequalities · Lesson 2

Systems of inequalities and their graphs

An inequality in xx and yy, such as y>2x−1y > 2x - 1, is true for a whole region of the xyxy-plane. A system of inequalities is solved by the points that make every inequality true at once. On a graph, that is where the shaded regions overlap.

To test a point, substitute its xx and yy into each inequality. If any one is false, the point is not a solution. A point that passes one inequality and fails the other is a common wrong answer on the SAT.

Each inequality's graph has two parts. The boundary line is the graph of the matching equation. It is dashed for << and >>, because points on the line are not solutions, and solid for ≤\le and ≥\ge, because they are. The shading shows the solutions: when the inequality is solved for yy, y>y > or y≥y \ge means above the line, and y<y < or y≤y \le means below it.

If the inequality isn't solved for yy, either solve it (and flip the sign if you divide by a negative) or test a point that is not on the line, such as (0,0)(0, 0). In 2x−3y<62x - 3y < 6, the point (0,0)(0, 0) gives 0<60 < 6, which is true, so the side containing the origin is shaded.

The questions in this course describe a graph in words instead of showing it: which points each line passes through, whether it is solid or dashed, and which side is shaded. On the SAT you may see the graph itself, and you read the same three features from it. Turn each line into y=mx+by = mx + b, then choose the sign from solid or dashed and above or below.

Worked example Easy

y>2x−1y > 2x - 1

y≤−x+5y \le -x + 5

Which point (x,y)(x, y) is a solution to the given system of inequalities?

  1. (0,3)(0, 3)Answer
  2. (1,1)(1, 1)
  3. (2,4)(2, 4)
  4. (3,2)(3, 2)

How to solve it

  1. Test (0,3)(0, 3). First inequality: 3>2(0)−1=−13 > 2(0) - 1 = -1, true. Second: 3≤−0+5=53 \le -0 + 5 = 5, true. It satisfies both.
  2. Each other point fails at least one inequality, so (0,3)(0, 3) is the only solution among the choices.

Why each choice is right or wrong

  • A. Correct. 3>−13 > -1 and 3≤53 \le 5, so (0,3)(0, 3) makes both inequalities true.
  • B. Incorrect. The first inequality gives 1>2(1)−1=11 > 2(1) - 1 = 1, which is false. The point lies on the boundary line y=2x−1y = 2x - 1, and that line is dashed because the sign is >>, so its points are not solutions.
  • C. Incorrect. It passes the first inequality, 4>34 > 3, but fails the second: 4≤−2+5=34 \le -2 + 5 = 3 is false.
  • D. Incorrect. It passes the second inequality, 2≤−3+5=22 \le -3 + 5 = 2, but fails the first: 2>2(3)−1=52 > 2(3) - 1 = 5 is false.

Worked example Medium

In the xyxy-plane, the solutions to a system of two linear inequalities are shown as a shaded region. One boundary is a solid line that passes through (0,1)(0, 1) and (2,5)(2, 5). The other is a dashed line that passes through (0,6)(0, 6) and (3,0)(3, 0). The shaded region lies on or above the solid line and below the dashed line.

Which system of inequalities is represented by the shaded region?

  1. y>2x+1y > 2x + 1 and y≤−2x+6y \le -2x + 6
  2. y≤2x+1y \le 2x + 1 and y>−2x+6y > -2x + 6
  3. y≥2x+1y \ge 2x + 1 and y<−2x+6y < -2x + 6Answer
  4. y≥12x+1y \ge \frac{1}{2}x + 1 and y<−12x+6y < -\frac{1}{2}x + 6

How to solve it

  1. Solid line: slope 5−12−0=2\frac{5 - 1}{2 - 0} = 2 and yy-intercept 1, so y=2x+1y = 2x + 1. Solid means the line is included, and the region is on or above it: y≥2x+1y \ge 2x + 1.
  2. Dashed line: slope 0−63−0=−2\frac{0 - 6}{3 - 0} = -2 and yy-intercept 6, so y=−2x+6y = -2x + 6. Dashed means the line is not included, and the region is below it: y<−2x+6y < -2x + 6.
  3. The system is y≥2x+1y \ge 2x + 1 and y<−2x+6y < -2x + 6.

Why each choice is right or wrong

  • A. Incorrect. The lines are right, but the signs are attached to the wrong lines. y>2x+1y > 2x + 1 would make the first line dashed, and y≤−2x+6y \le -2x + 6 would make the second one solid.
  • B. Incorrect. The lines are right, but the shading is reversed. y≤y \le shades below the first line and y>y > shades above the second, the opposite of the description.
  • C. Correct. The solid line is y=2x+1y = 2x + 1 with the region on or above it, and the dashed line is y=−2x+6y = -2x + 6 with the region strictly below it.
  • D. Incorrect. This computes each slope as run over rise: 24=12\frac{2}{4} = \frac{1}{2} and 3−6=−12\frac{3}{-6} = -\frac{1}{2}. Slope is rise over run, so the slopes are 2 and −2-2.

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