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98 questions across four modules, in the digital SAT’s order and on its timing, with a highlighter, a question map and a timer you can see.

A Peakscor full-length test in progress: Reading and Writing, Test A, Module 1 of 4, question 7 of 27, with the passage, four answer choices, a highlighter, a 24:18 timer and Flag, Back and Next buttons.

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Every question is tagged by section, domain, skill and difficulty, so you can practice exactly what you need. Full tests run like test day: two Reading & Writing modules, a break, then two Math modules.

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MathProblem-Solving and Data AnalysisHard

A store raises the price of a jacket by 20%. Later, it lowers the new price by 20%. The final price is what percent of the original price?

A80%
B96%Correct
C100%The trap
D104%

Check with $100: $100then$120then$96

  1. Turn each change into a multiplier.

    Up 20% means × 1.20. Down 20% means × 0.80.

  2. Apply them in order.

    1.20 × 0.80 = 0.96

  3. Read the answer.

    The final price is 96% of the original. That’s B.

  4. Why not 100%?

    The 20% cut is taken from the higher price, so it removes more than the 20% increase added.

Test day

What test day looks like.

Every Peakscor full test follows this order. In the standard tests, the second module of each section adapts to how you did on the first.

  1. Reading & Writing · Module 1

    27 questions32 min

  2. Reading & Writing · Module 2

    27 questions32 min

    Adapts to how you did on Module 1.
  3. Break

    10 min

  4. Math · Module 1

    22 questions35 min

  5. Math · Module 2

    22 questions35 min

    Adapts to how you did on Module 1.

98 questions · 2 hr 14 min of testing, plus the break

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FAQ

Questions, answered.

The Daily, plus 36 practice questions every day: 12 easy, 12 medium and 12 hard, each with a full explanation. Full-length Test A, Challenge Test 1 and all 1,023 vocabulary words are free too. No card needed.

Pro is $20 a month or $200 a year: unlimited practice with no daily limit, plus every full-length test and Challenge test. Peak is $29 a month or $280 a year: everything in Pro, plus the full Learn course and Peak Plan. Cancel anytime from your account.

98 questions across four modules, in the digital SAT’s order: Reading & Writing Module 1 and Module 2 (27 questions each), a 10-minute break, then Math Module 1 and Module 2 (22 questions each). On official timing that’s 2 hr 14 min of testing. You get estimated section scores and a total at the end.

Yes. In the standard full-length tests, Module 2 of each section is the harder version if you get 60% or more of Module 1 right, and the easier version if you don’t. Challenge tests use the hardest material throughout.

Official timing, extended 1.5× time, or untimed, on every test, including the free ones. Extended time allows 48 minutes for each Reading & Writing module and about 52 for each Math module. Untimed removes the clock so you can focus on accuracy.

A quick run with three hearts. Each right answer builds your streak: the questions get harder as it grows, and your points multiply (×2 from three in a row, ×3 from six). A miss costs a heart and drops you back to easy. Best is your longest streak.

Every day at midnight. You get a fresh 12 easy, 12 medium and 12 hard.

No. Peakscor is an independent SAT practice tool, not affiliated with the College Board. Scores shown are estimates.

Your next point starts today.

Free, no card.

Equivalent expressions · Lesson 2

Factoring

Factoring runs expanding backward: you write an expression as a product. On the SAT it helps you spot an equivalent form, find a factor, or simplify a fraction.

Greatest common factor (GCF) first. Pull out the largest factor every term shares: 6x3−15x=3x(2x2−5)6x^3 - 15x = 3x(2x^2 - 5). The GCF stays in front of the final answer.

**Trinomials x2+bx+cx^2 + bx + c.** Find two numbers that multiply to cc and add to bb. For x2+2x−15x^2 + 2x - 15: 5⋅(−3)=−155 \cdot (-3) = -15 and 5+(−3)=25 + (-3) = 2, so it is (x+5)(x−3)(x + 5)(x - 3).

**Trinomials ax2+bx+cax^2 + bx + c with a≠1a \ne 1.** Find two numbers that multiply to acac and add to bb, split the middle term with them, and factor by grouping. For 2x2+7x+32x^2 + 7x + 3: ac=6ac = 6, and 6⋅1=66 \cdot 1 = 6 with 6+1=76 + 1 = 7. So 2x2+6x+x+3=2x(x+3)+1(x+3)=(2x+1)(x+3)2x^2 + 6x + x + 3 = 2x(x + 3) + 1(x + 3) = (2x + 1)(x + 3).

Difference of squares. a2−b2=(a−b)(a+b)a^2 - b^2 = (a - b)(a + b). Look for structure: 4x2−49=(2x)2−72=(2x−7)(2x+7)4x^2 - 49 = (2x)^2 - 7^2 = (2x - 7)(2x + 7), and x4−16=(x2)2−42=(x2−4)(x2+4)x^4 - 16 = (x^2)^2 - 4^2 = (x^2 - 4)(x^2 + 4). The x2−4x^2 - 4 factors again into (x−2)(x+2)(x - 2)(x + 2). A sum of squares such as x2+4x^2 + 4 does not factor into binomials with real numbers.

Check any factoring by expanding it back. If you get the original expression, it's right.

Worked example Easy

Which expression is equivalent to x2−3x−28x^2 - 3x - 28?

  1. (x+7)(x−4)(x + 7)(x - 4)
  2. (x−7)(x+4)(x - 7)(x + 4)Answer
  3. (x−7)(x−4)(x - 7)(x - 4)
  4. (x−14)(x+2)(x - 14)(x + 2)

How to solve it

  1. Look for two numbers that multiply to −28-28 and add to −3-3.
  2. The product is negative, so the numbers have opposite signs. The sum is negative, so the number farther from zero is negative: −7-7 and 4.
  3. Write (x−7)(x+4)(x - 7)(x + 4). Check: x2+4x−7x−28=x2−3x−28x^2 + 4x - 7x - 28 = x^2 - 3x - 28.

Why each choice is right or wrong

  • A. Incorrect. The signs are swapped. (x+7)(x−4)=x2+3x−28(x + 7)(x - 4) = x^2 + 3x - 28, with a middle term of +3x+3x.
  • B. Correct. −7⋅4=−28-7 \cdot 4 = -28 and −7+4=−3-7 + 4 = -3. Expanding gives x2+4x−7x−28=x2−3x−28x^2 + 4x - 7x - 28 = x^2 - 3x - 28.
  • C. Incorrect. −7-7 and −4-4 multiply to +28+28, not −28-28. This expands to x2−11x+28x^2 - 11x + 28.
  • D. Incorrect. −14-14 and 2 multiply to −28-28, but they add to −12-12, not −3-3. This expands to x2−12x−28x^2 - 12x - 28.

Worked example Medium

Which expression is equivalent to 6x2+7x−206x^2 + 7x - 20?

  1. (3x+4)(2x−5)(3x + 4)(2x - 5)
  2. (3x−4)(2x+5)(3x - 4)(2x + 5)Answer
  3. (6x−5)(x+4)(6x - 5)(x + 4)
  4. (x−43)(x+52)\left(x - \frac{4}{3}\right)\left(x + \frac{5}{2}\right)

How to solve it

  1. Multiply aa and cc: 6⋅(−20)=−1206 \cdot (-20) = -120. Find two numbers that multiply to −120-120 and add to 7: 15 and −8-8.
  2. Split the middle term: 6x2+15x−8x−206x^2 + 15x - 8x - 20.
  3. Group: 3x(2x+5)−4(2x+5)3x(2x + 5) - 4(2x + 5).
  4. Factor out 2x+52x + 5: (3x−4)(2x+5)(3x - 4)(2x + 5). Check: 6x2+15x−8x−20=6x2+7x−206x^2 + 15x - 8x - 20 = 6x^2 + 7x - 20.

Why each choice is right or wrong

  • A. Incorrect. The signs are swapped. (3x+4)(2x−5)=6x2−15x+8x−20=6x2−7x−20(3x + 4)(2x - 5) = 6x^2 - 15x + 8x - 20 = 6x^2 - 7x - 20, with a middle term of −7x-7x.
  • B. Correct. Expanding gives 6x2+15x−8x−20=6x2+7x−206x^2 + 15x - 8x - 20 = 6x^2 + 7x - 20.
  • C. Incorrect. The first terms multiply to 6x26x^2 and the last terms to −20-20, but the middle products are 24x24x and −5x-5x, which give 19x19x, not 7x7x. Always check the middle term.
  • D. Incorrect. This has the right zeros, 43\frac{4}{3} and −52-\frac{5}{2}, but its x2x^2-coefficient is 1. It equals 16(3x−4)(2x+5)\frac{1}{6}(3x - 4)(2x + 5), one sixth of the given expression. An equivalent form must keep the leading coefficient 6.

Worked example Hard

Which expression is equivalent to 2x4−322x^4 - 32?

  1. 2(x2−4)22(x^2 - 4)^2
  2. 2(x−2)42(x - 2)^4
  3. 2(x−2)(x+2)(x2+4)2(x - 2)(x + 2)(x^2 + 4)Answer
  4. (x−2)(x+2)(x2+4)(x - 2)(x + 2)(x^2 + 4)

How to solve it

  1. Pull out the GCF, 2: 2(x4−16)2(x^4 - 16).
  2. See x4−16x^4 - 16 as a difference of squares: (x2)2−42=(x2−4)(x2+4)(x^2)^2 - 4^2 = (x^2 - 4)(x^2 + 4).
  3. x2−4x^2 - 4 is another difference of squares: (x−2)(x+2)(x - 2)(x + 2). The sum x2+4x^2 + 4 does not factor.
  4. Result: 2(x−2)(x+2)(x2+4)2(x - 2)(x + 2)(x^2 + 4).

Why each choice is right or wrong

  • A. Incorrect. This writes x4−16x^4 - 16 as (x2−4)(x2−4)(x^2 - 4)(x^2 - 4). But (x2−4)2=x4−8x2+16(x^2 - 4)^2 = x^4 - 8x^2 + 16, so this choice equals 2x4−16x2+322x^4 - 16x^2 + 32. A difference of squares factors into one minus and one plus factor: (x2−4)(x2+4)(x^2 - 4)(x^2 + 4).
  • B. Incorrect. This assumes x4−16=(x−2)4x^4 - 16 = (x - 2)^4, as if each term could be raised to the fourth power separately. At x=0x = 0, 2(x−2)4=322(x - 2)^4 = 32, but 2x4−32=−322x^4 - 32 = -32.
  • C. Correct. 2x4−32=2(x4−16)=2(x2−4)(x2+4)=2(x−2)(x+2)(x2+4)2x^4 - 32 = 2(x^4 - 16) = 2(x^2 - 4)(x^2 + 4) = 2(x - 2)(x + 2)(x^2 + 4). Expanding back: (x−2)(x+2)=x2−4(x - 2)(x + 2) = x^2 - 4, times x2+4x^2 + 4 is x4−16x^4 - 16, times 2 is 2x4−322x^4 - 32.
  • D. Incorrect. This factors x4−16x^4 - 16 correctly but drops the GCF. It equals x4−16x^4 - 16, half of the given expression.

Trap Right ends, wrong middle

For ax2+bx+cax^2 + bx + c, many pairs of factors give the right first and last terms. Only one pair also gives the middle term. The SAT often lists pairs that match the ends but not the middle, and the version with the signs swapped. Expand your answer to check the middle term.

Trap Stopping early or losing the GCF

x4−16=(x2−4)(x2+4)x^4 - 16 = (x^2 - 4)(x^2 + 4) is true, but x2−4x^2 - 4 still factors. If the question asks for a factor such as x−2x - 2, you need that last step. And if you pulled out a GCF, it stays in the answer: (x−2)(x+2)(x2+4)(x - 2)(x + 2)(x^2 + 4) is half of 2x4−322x^4 - 32, not equal to it.

Desmos When Desmos is faster

For which expression is equivalent questions, graph the original and each choice as y=y = lines. The equivalent choice lies exactly on top of the original.

For which expression is a factor questions, graph y=y = the expression and click the points where it meets the xx-axis. For a polynomial, a zero at x=rx = r means x−rx - r is a factor. For 6x2+7x−206x^2 + 7x - 20, the intercepts are at x=−2.5x = -2.5 and x≈1.333x \approx 1.333, which match the factors 2x+52x + 5 and 3x−43x - 4. Desmos shows decimals, so connect 1.333 to 43\frac{4}{3} yourself.

Intercepts only find factors with real zeros. A factor such as x2+4x^2 + 4 never meets the xx-axis, so for a choice like that, compare graphs or expand by hand instead.

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Full-length tests

Each test mirrors the digital SAT: 98 questions across four modules, 2 hr 14 min on official timing.

A little harder than the real SAT. These tests can run slightly tougher than test day, which makes them good practice: if you can handle these, the real one should feel easier. No question appears in more than one test, Challenge Tests included.

Challenge Tests Hardest of the hardest

Same 98-question format, but every question is drawn from the toughest SAT material: Challenging-tier math throughout and the hardest reading.

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Study the classic SAT vocabulary list. Browse, flip flashcards, or quiz yourself.

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